But if you replace -3 it shows you a different number... So its not the correct answer
How Do I Solve (1/x)=(4/3x)+1?
(1/x) = (4/3x)+1 multiply both sides by 3x2 3x2(1/x) = 3x2 (4/3x) + 3x2 => 3x = 4x + 3x2 => 3x2+x = 0 => x(3+x) = 0 Hence, either x = 0 or 3+x = 0 i.e. X = -3 Hope you like the answers.
