5t^2 -10t=0 And X^2-3x -10=0, Can You Solve This By Factoring?

5t² -10t = 0

(5t)(t - 2) = 0

Either t5 = 0 or t - 2 = 0 which means that t = 0 or t = 2.

x²-3x -10=0

x²-5x -2x-10=0

x(x-5) -2(x-5)=0

(x-5)(x-2)=0

Therefore, either (x-5)=0 or (x-2)=0 and in this case x = 5 or x = 2.