What is the answer to Multiply. 1B7twelve x 29twelve?

1B7 twelve x 29 twelve

= 1B7 twelve x 9 twelve plus 1B7 twelve x 20 twelve

First 1B7 twelve x 9 twelve is sum of 100 twelve x 9 twelve + B0 twelve x 9 twelve + 7 twelve x 9 twelve

in base 10

7 x 9 = 63 = and that equals 53 twelve

Next

B0 twelve x 9 twelve is 11x12 in base 10 + 0 base 10 and that's 132

since 132 x 9 = 1188 in base ten. . 1188 = 8 x 144 + 3 x 12 + 0 x 1

so 1188 = 830 twelve

Now 100 twelve times 9 twelve = 900 twelve so

we have to add 53 twelve + 830 twelve + 900 twelve

the ones column adds to 3, then twelves column is 5+3 =8 and the

hundredfortyfours column is 8+9 = 17 base 10 which is 15 twelve

so B0 twelve times 9 twelve equals 1583 twelve

Now we have to determine

1B7 twelve x 20 twelve

1B7 twelve times 2 twelve is 200 twelve plus (22 base 10) x 10 twelve + 14 base 10

and that is 200 twelve + 1A0 twelve + 12 twelve

= 3B2 twelve.

We need to put a zero after that so it is 3B20

The final product is equal to 1583 twelve + 3B20 twelve

and that is 4 [16]A3 twelve. We must get rid of that base 10 sixteen.

Sixteen is 14 twelve so we put the 4 and carry the 1 and result is

54A3 twelve