Solve the system of equations: 5x+6y+8=0 3x-2y+16=0?

(5x + 6y + 8) + 3(3x - 2y + 16) = 0 + 3(0)    (add 3 times the second equation to the first)
5x + 6y + 8 + 9x - 6y + 48 = 0    (eliminate parentheses)
14x + 56 = 0    (collect terms)
x + 4 = 0    (divide by 14)
x = -4    (subtract 4)

3(-4) - 2y + 16 = 0    (substitute for x in the second equation)
4 - 2y = 0    (collect terms)
2 - y = 0    (divide by 2)
2 = y    (add y)

The solution is (x, y) = (-4, 2).

5x+6y+8=0 and 3x-2y+16=0
5x+6y=-8 and 3x-2y=-16
to solve this we'll eliminate that equation
5x+6y=-8  (times by 3)
3x-2y=-16 (times by 5)

15x+18y=-24
15x-10y=-80
~~~~~~~~  -
0  +28y= 56
          y= 56/28
          y=2
to find x just put the number into this equation
5x+6y=-8
5x+6(2)=-8
5x=-8-12
5x=-20
  x=-4
SO, X=-4 AND Y=2