You have a 1/8 probability of choosing a 4.
1, 2, 3, 4, 5, 6, 7, 8
------Independent occurrences.
You have a 1/4 chance of pulling an odd number.
1, 3, 5, 7
------
Please help, I really need the answer to this. On a fair spinner with 8 equal sections... What is the probability of choosing 4 AND THEN choosing an odd number? (The answer must be a fraction)
I'd never dream of challenging John's math - and what he says is correct.
But, in a single sitting where one action occurs after the other, the odds of both happening, one after the other is 1/8 * 1/4 = 1/32
You have two correct answers and here's why:
If A and B are independent events,
P(A and B) = P(A) • P(B).
