How Do You Solve For X^2-3x-40?

X^2-3x-40
In this question, you need to split -3 in such a way that the numbers add up to form -3 and Multiply to form -40, Here -40 is Product of 1 from X² AND -40]
X²-3x-40
Let X²-3x-40=0
X²-8x+5x-40=0 [Making -3 Split as mentioned above]
X(X-8)+5(X-8)=0
(X+5)(X+8)=0
Now, X+5=0    AND     X-8=0
X= -5     AND    X=8
X=(-5,8)