6√3 is the length of the cube's diagonal.
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The diagonal of the cube runs through the center of the cube between opposite corners. It is the hypotenuse of a triangle formed by one edge and the diagonal of one face.
62 + (6√2)2 = d2 = 36 + 36*2 = 36*3
d = √(36*3) = 6√3
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The diagonal of the cube runs through the center of the cube between opposite corners. It is the hypotenuse of a triangle formed by one edge and the diagonal of one face.
62 + (6√2)2 = d2 = 36 + 36*2 = 36*3
d = √(36*3) = 6√3
