G(x)=e^x-5
The graph is shifted 5 units downwards.
The horizontal asymptote is at y= -5 as it used to be at zero but as the entire graph is shifted downwards, so it went
from y=0 to y = -5.
the y intercepts is when x = 0
therefore,
G(x)=e^x-5
G(0) = (e^0) - 5
= 1 - 5
= -4
so (x,y) = (0,.4)
H(x)=-e^x
The graph is reflected across the x-axis. The horizontal asymptote is in the same place but the y-intercept = (0,-1)
The graph is shifted 5 units downwards.
The horizontal asymptote is at y= -5 as it used to be at zero but as the entire graph is shifted downwards, so it went
from y=0 to y = -5.
the y intercepts is when x = 0
therefore,
G(x)=e^x-5
G(0) = (e^0) - 5
= 1 - 5
= -4
so (x,y) = (0,.4)
H(x)=-e^x
The graph is reflected across the x-axis. The horizontal asymptote is in the same place but the y-intercept = (0,-1)