Using truth table, prove that:
(A + B) . C = (A . C) + (B . C) (Marks 10)
Solution:
there are 3 variables a b c
so 2^n
so 2^3
2*2*2=8 values
A------B------C----(A+B)--(A+B).C ===(A.C)----(B.C)----(A.C)+(B.C)
0------0------0------0------0======0------0------0
0------0------1------0------0======0------0------0
0------1------0------1------0======0------0------0
0------1------1------1------1======0------1------1
1------0------0------1------0======0------0------0
1------0------1------1------1======1------0------1
1------1------0------1------0======0------0------0
1------1------1------1------1==
(A + B) . C = (A . C) + (B . C) (Marks 10)
Solution:
there are 3 variables a b c
so 2^n
so 2^3
2*2*2=8 values
A------B------C----(A+B)--(A+B).C ===(A.C)----(B.C)----(A.C)+(B.C)
0------0------0------0------0======0------0------0
0------0------1------0------0======0------0------0
0------1------0------1------0======0------0------0
0------1------1------1------1======0------1------1
1------0------0------1------0======0------0------0
1------0------1------1------1======1------0------1
1------1------0------1------0======0------0------0
1------1------1------1------1==