Using truth table, prove that:

(A + B) . C = (A . C) + (B . C) (Marks 10)

Solution:

there are 3 variables a b c

so 2^n

so 2^3

2*2*2=8 values

A------B------C----(A+B)--(A+B).C ===(A.C)----(B.C)----(A.C)+(B.C)

0------0------0------0------0======0------0------0

0------0------1------0------0======0------0------0

0------1------0------1------0======0------0------0

0------1------1------1------1======0------1------1

1------0------0------1------0======0------0------0

1------0------1------1------1======1------0------1

1------1------0------1------0======0------0------0

1------1------1------1------1==

(A + B) . C = (A . C) + (B . C) (Marks 10)

Solution:

there are 3 variables a b c

so 2^n

so 2^3

2*2*2=8 values

A------B------C----(A+B)--(A+B).C ===(A.C)----(B.C)----(A.C)+(B.C)

0------0------0------0------0======0------0------0

0------0------1------0------0======0------0------0

0------1------0------1------0======0------0------0

0------1------1------1------1======0------1------1

1------0------0------1------0======0------0------0

1------0------1------1------1======1------0------1

1------1------0------1------0======0------0------0

1------1------1------1------1==