N(Al2O3)=25.0/102=0.245mole, n(AlCl3)=2*0.245=0.29mole
m=0.29*133.5=65.415g.
m=0.29*133.5=65.415g.
Find The Mass Of AlCl3 That Is Produced When 25.0 Grams Of Al2O3 React With HCl According To The Following Balanced Equation?