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What is the sum of the polynomials 3a2b + 2a2b2 and –ab2 + a2b2?

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yuan hui answered
(3a2b + 2a2b2) +(–ab2 + a2b2)=3a2b–ab2+3a2b2so the answer is 3a2b–ab2+3a2b2.

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