(3a2b + 2a2b2) +(–ab2 + a2b2)=3a2b–ab2+3a2b2so the answer is 3a2b–ab2+3a2b2.
What is the sum of the polynomials 3a2b + 2a2b2 and –ab2 + a2b2?
(3a^2b +2a^2b^2) + (-ab^2 + a^2b^2)
3a^2b + 3a^2b^2 - ab^2
3a^2b + 3a^2b^2 - ab^2