(3a

^{2}b + 2a^{2}b^{2)}+(–ab^{2}+ a^{2}b^{2})=3a^{2}b–ab^{2}+3a^{2}b^{2}so the answer is 3a^{2}b–ab^{2}+3a^{2}b^{2}.(3a^2b +2a^2b^2) + (-ab^2 + a^2b^2)

3a^2b + 3a^2b^2 - ab^2

3a^2b + 3a^2b^2 - ab^2

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