The area of quadrilateral ABCD whose sides are 9 m, 40 m, 28 m and 15 m is?


2 Answers

Oddman Profile
Oddman answered
The side lengths of a quadrilateral are not sufficient to define the figure. The area cannot be figured with this information alone.

If you have other information about the quadrilateral, then the area can be computed. You might know, for example, that there is one right angle, that two sides are parallel, that the diagonals cross at right angles, or the length of a diagonal. Any of these bits of additional information is sufficient to finish the definition of the figure.

Consider sticks in relative lengths of 9, 15, 28, and 40. Consider how you might arrange them in a quadrilateral. You will quickly find that there are multiple ways to do it--each having a different area.
Kellen Moen Profile
Kellen Moen answered
Simple: 9 m x 40 m x 28 m x 15 m = 151200m

area is the amount of space inside a figure.
thanked the writer.
Oddman commented
The units of your product are not m, but m^4. Your figure's volume in four dimensions has no relation to the area of a quadrilateral, which has the units of m^2.

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