Radioactive decay obeys the law,C(t) = C(0) x e^(-Lt)
where
where
C(t) = Concentration left after t days
C(0) = Concentration of original sample = Concentration at t = 0 days
L = 1 / (Half Life)
Now when t = 50, C(50) = C(0)/2
=>1/2 = e^(-L 50)
=> L = (ln 2) / 50 = 0.013863 / day
Now substituting t = 60 days
C (60) = C(0) e^(-ln 2/50 x 60) = C(0) e^(- 0.013863 x 60) = C(0) 0.435274
Percentage of original sample left = [C(60)/C(0)] x 100 = 0.435274 x 100 = 43.527 %
C(0) = Concentration of original sample = Concentration at t = 0 days
L = 1 / (Half Life)
Now when t = 50, C(50) = C(0)/2
=>1/2 = e^(-L 50)
=> L = (ln 2) / 50 = 0.013863 / day
Now substituting t = 60 days
C (60) = C(0) e^(-ln 2/50 x 60) = C(0) e^(- 0.013863 x 60) = C(0) 0.435274
Percentage of original sample left = [C(60)/C(0)] x 100 = 0.435274 x 100 = 43.527 %
