# Hi.. I just wanted to know how many 5 digits combination can be made from the digits 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15?

As written, the question appears to not make sense. Perhaps you will like to rephrase it to ask, "How many 5 digit integers can be made from the digits 1 -9?". The solution to this is:

9 * 8 * 7 * 6 * 5 = 15120 possible numbers ______
There are 9 feasible choices for the first digit (any of the digits 1 - 9). Once this has been chosen, 8 choices remain for the second digit, 7 choices remain for the third digit, 7 choices remain for the third digit, 6 choices remain for the fourth digit and 5 choices remain for the final digit. Hence, the total combinations are: (9 * 8 * 7 * 6 * 5) feasible numbers.
thanked the writer.
hemanth kumar commented
Thanks for your reply.. I wanted to know that how many 5 digits combination can be formed using digits 1 to 15.??
Shashank Singh commented
1+3+5+7+9+11+13+15+17+19=100

or it can be written as ----

0+1+3+5+7+9+11+13+15+17+19=100
then

0+5+13+15+17=50
15 nPr 5 = 360,360 (using #s 1 - 15 only once per combination)  It's 15 X 14 X 13 X 12 X 11  I'm assuming you mean numbers and not digits
thanked the writer.
hemanth kumar commented
OOPs sry if my words are confusing.... Yes i meant how many 5 number combination can be made using digits 1to 15.. And also i wanted the list of those 5 no combination which can be made using digits 1 to 15..

And thanks very much for instant reply.. I like it :P
Shashank Singh commented
1+3+5+7+9+11+13+15+17+19=100

or it can be written as ----

0+1+3+5+7+9+11+13+15+17+19=100
then

0+5+13+15+17=50