As written, the question appears to not make sense. Perhaps you will like to rephrase it to ask, "How many 5 digit integers can be made from the digits 1 -9?". The solution to this is:

9 * 8 * 7 * 6 * 5 =

There are 9 feasible choices for the first digit (any of the digits 1 - 9). Once this has been chosen, 8 choices remain for the second digit, 7 choices remain for the third digit, 7 choices remain for the third digit, 6 choices remain for the fourth digit and 5 choices remain for the final digit. Hence, the total combinations are: (9 * 8 * 7 * 6 * 5) feasible numbers.

9 * 8 * 7 * 6 * 5 =

**15120 possible numbers**______There are 9 feasible choices for the first digit (any of the digits 1 - 9). Once this has been chosen, 8 choices remain for the second digit, 7 choices remain for the third digit, 7 choices remain for the third digit, 6 choices remain for the fourth digit and 5 choices remain for the final digit. Hence, the total combinations are: (9 * 8 * 7 * 6 * 5) feasible numbers.