The sum of three numbers is 2008. The second is 2 less than twice the first and the third is 9 more than thrice the second."The sum of three numbers is 2008."

__sum__, meaning adding these three variables together, will give 2008.

z = 3y + 9 (I also simplified this equation so that I could find the value of z more easily.)

We technically have values for y and z, in which we can plug them into the original equation we had, which was x + y + z = 2008. Plugging them in, we will get:

x + (2x - 2) + (3y + 9) = 2008

But hang on, there's still a y variable in the equation, and we have a value for y, so we can plug in more values.

x + (2x - 2) + [3(2x - 2) + 9] = 2008

Now we must simplify the equation and solve for x.

x + 2x - 2 + (6x - 6 + 9) = 2008

3x - 2 + 6x + 3 = 2008

9x + 1 = 2008

9x = 2007

**x = 223**

Now that we have a value for x, we can plug this into the other two equations for y and z

y = 2x - 2

y = 2(223) - 2

y = 446 - 2

**y = 444**

z = 3y + 9

z = 3(444) + 9

z = 1332 + 9

**z = 1341**

The three numbers are: **x = 223**,** y = 444**, and **z = 1341**.