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given:f(x)=(x^2-9)^(1/2), find:f(x-3)?

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David Shabazi answered

Given f(x), to find f(x-3), you have to plug in (x-3) to everywhere you see (x) in the original function.

f(x - 3) = [(x - 3)^2 - 9]^(1/2)

Notice how I replaced the x with x - 3. Now just simplify the function.

f(x - 3) = (x^2 - 6x + 9 - 9)^(1/2)

= sqrt(x^2 - 6x)

****(Anything to the power of (1/2) is the same thing as taking the square root of it.)

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