The concession stand at an ice hockey rink had receipts of $7000 from selling a total of 3000 sodas and hot dogs. If each soda sold for 2 and each hot dog sold for 3, how many of each were sold?

2 Answers

John McCann answered

This is a systems problem. Two variables to find. ( I assume that 2 and 3 means dollars )

S = sodas

D = hot dogs

S + D = 3000

2S + 3D = $7000

We will use substitution with the top equation.

D = 3000 - S

------Now, substitute this into bottom equation

2S + 3(3000 - S) = .7000

2S + 9000 - 3S = 7000

- S = - 2000

S = 2000

------Sodas are 2000 in number sold.

So, 1000 hot dogs were sold.

Anonymous answered

Yes, the person above is right - 2 and 3 should be in dollars, so the question should be asked asThe concession stand at an ice hockey rink had receipts of $7000 from selling a total of 3000 sodas and hot dogs. If each soda sold for $2 and each hot dog sold for $3, how many of each were sold?

But the answer should not be in dollars though, because you're trying to count out how many were sold - not how much they were sold for.

And yeah, 1000 hot dogs is the correct answer. I got my assignment back and copied the answer above and it was right (:

The concession stand at an ice hockey rink had receipts of $7000 from selling a total of 3000 sodas and hot dogs. If each soda sold for 2 and each hot dog sold for 3, how many of each were sold?

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