One number is 5 more than twice another number. If the difference of the two numbers is 7, what are the two numbers?

Looks like a system of equations will solve this.

X = one number

Y = another number

-----------------------------------

X - Y = 7

X = 2Y + 5
-------------------------------------Rearrange top equation.

X = 7 + y

--------------Insert into bottom equation.

7 + Y = 2Y +5

7 = Y + 5

2 = Y

=========Find X in top first equation ( X - Y = 7)

X - 2 = 7

X = 9

======You have checked one equation, now check this original equation.

X = 2Y + 5

9 = 2(2) + 5

9 = 9

=======Checks and is consistent.

Y = 2

X = 9