⁸C₂ × ⁴C₁ + ⁸C₂ × ⁴C₂
= 28 × 4 + 28 × 6
= 280
There are 8 counc and 4 staf available to serve on a committee, will consist of 2 counc and either 1 or 2 planning staff, how many different commitys?
⁸C₂ × ⁴C₁ + ⁸C₂ × ⁴C₂
= 28 × 4 + 28 × 6
= 280
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