Find probability forgetting exactly 4heads,3tails and at most 3
What Is The Probability Of Getting 4 Heads, When The Coin Is Tossed 9 Times?
What is the probability that a head shows up the first 5 times and a tail shows up the rest of the times, when a coin is tossed 10 times?
It is a question of binomial distribution. According to the binomial distribution;
P(x) = nCx px qn-x
P(x)= probability
n= number of trails
x= possible outcome
p= probability of success
q= probability of failure
In the given question;
p= 1/2, q=1/2, x= 4, and n=9
P(x=4)= 9C4(1/2)4(1/2)5
P(x=4)=126* 0.0625 * 0.03125
P(x=4)= 0.246
P(x) = nCx px qn-x
P(x)= probability
n= number of trails
x= possible outcome
p= probability of success
q= probability of failure
In the given question;
p= 1/2, q=1/2, x= 4, and n=9
P(x=4)= 9C4(1/2)4(1/2)5
P(x=4)=126* 0.0625 * 0.03125
P(x=4)= 0.246