X3+3x2-2x+7 Divided By X+1 The Remainder Is?

The question is:
x³+3x²-2x+7
x+1
taking common
X(x²+3x-2)+7
x+1
making factors
X(x²+2x+x+2)+7
x+1
taking common
X(x(x+2)+1(x+2)+7
x+1
So
X(X+2)(x+1)+7
(x+1)
(x+1) in the denominator cancels with the (x+1) in the numerator. So

X(X+2)+7
Which when expanded:
x²+2x+7