The x coordinate of the vertex of y = ax^2+bx+c is given by x=-b/(2a). For your equation, this is

x = -(4)/(2*-1) = -4/-2 = 2

The equation evaluated at x=2 is

y = -(2

= -4+8+5

= 9

The coordinates of the vertex are (x, y) = (2, 9)

x = -(4)/(2*-1) = -4/-2 = 2

The equation evaluated at x=2 is

y = -(2

^{2}) + 4(2) + 5= -4+8+5

= 9

The coordinates of the vertex are (x, y) = (2, 9)