The Present Ages Of Three Persons Are In Proportions 4 : 7 : 9. Eight Years Ago, The Sum Of Their Ages Was 56. Can You Find Their Present Ages (in Years)?

Collectively, they are 24 years older than they were 8 years ago.
The youngest is 4/(4+7+9)*(56+24) = 4/20*80 = 16
The one in the middle is 7/20*80 = 28
The oldest is 9*4 = 36

Their present ages are 16, 28, 36.