Area formula is A=LW

Perimeter formula is P = 2L + 2W

P = 18

A = 18

Using the area formula

18 = LW

solve for L

L = 18/W

Substitute the 18/W for the L in the Perimeter formula

18 = 2(18/W) + 2W

18 = 36/W + 2W

36/W + 2W - 18 = 0

multiply both sides by W

36 + 2W

2W

factor it

(2W - 6)(W - 6) = 0

2W - 6 = 0 W - 6 = 0

2W = 6 W = 6

W = 3

A=LW A=LW

18=L3 18=L6

L=6 L=3

So, one rectangle has a Length of 6 and a Width of 3

The second rectangle has a Length of 3 and a Width of 6.

Perimeter formula is P = 2L + 2W

P = 18

A = 18

Using the area formula

18 = LW

solve for L

L = 18/W

Substitute the 18/W for the L in the Perimeter formula

18 = 2(18/W) + 2W

18 = 36/W + 2W

36/W + 2W - 18 = 0

multiply both sides by W

36 + 2W

^{2}- 18W = 02W

^{2}- 18W + 36 = 0factor it

(2W - 6)(W - 6) = 0

2W - 6 = 0 W - 6 = 0

2W = 6 W = 6

W = 3

A=LW A=LW

18=L3 18=L6

L=6 L=3

So, one rectangle has a Length of 6 and a Width of 3

The second rectangle has a Length of 3 and a Width of 6.