You can find the two real solutions by factoring the equation.
(x-3)(x-4) = 0
You can determine the number and kind of solutions by looking at the value of the discriminant.
B^2 - 4ac = (-7)^2 - 4*1*12 = 49-48 = 1
The discriminant is positive, so there are two real solutions.
(x-3)(x-4) = 0
You can determine the number and kind of solutions by looking at the value of the discriminant.
B^2 - 4ac = (-7)^2 - 4*1*12 = 49-48 = 1
The discriminant is positive, so there are two real solutions.