You can find the

(x-3)(x-4) = 0

You can determine the number and kind of solutions by looking at the value of the discriminant.

B^2 - 4ac = (-7)^2 - 4*1*12 = 49-48 = 1

The discriminant is positive, so there are

**two real solutions**by factoring the equation.(x-3)(x-4) = 0

You can determine the number and kind of solutions by looking at the value of the discriminant.

B^2 - 4ac = (-7)^2 - 4*1*12 = 49-48 = 1

The discriminant is positive, so there are

**two real solutions**.