When Two Congruent Equilateral Triangles Share A Common Center, Their Union Can Be A Star, As Shown. If Their Overlap Is A Regular Hexagon With An Area Of 60, What Is The Area Od One Of The Original Equilateral Triangles?

Given, the area of the hexagon formed by the overlap of two equilateral triangles is 60.
Let the side of that hexagon is a,
thn area of hexagon is:3 * sqrt(3) * a * a=60   - - - eq(1)
and the side of the triangle : 3a (since side of hexagon is assumed as a)
Therefore area of original equilateral triangle is: (srqt(3)  * (3a) *(3a) ) / 2
  by rearranging the above terms  ((3 * sqrt(3) * a * a) * 3 )/2
  substituting eq(1) we get (60 * 3)/2
  =90.
Therefore area of original equilateral triangle is: 90.