Given, the area of the hexagon formed by the overlap of two equilateral triangles is 60.

Let the side of that hexagon is a,

thn area of hexagon is:3 * sqrt(3) * a * a=60 - - - eq(1)

and the side of the triangle : 3a (since side of hexagon is assumed as a)

Therefore area of original equilateral triangle is: (srqt(3) * (3a) *(3a) ) / 2

by rearranging the above terms ((3 * sqrt(3) * a * a) * 3 )/2

substituting eq(1) we get (60 * 3)/2

=90.

Therefore area of original equilateral triangle is: 90.

Let the side of that hexagon is a,

thn area of hexagon is:3 * sqrt(3) * a * a=60 - - - eq(1)

and the side of the triangle : 3a (since side of hexagon is assumed as a)

Therefore area of original equilateral triangle is: (srqt(3) * (3a) *(3a) ) / 2

by rearranging the above terms ((3 * sqrt(3) * a * a) * 3 )/2

substituting eq(1) we get (60 * 3)/2

=90.

Therefore area of original equilateral triangle is: 90.