Three Consecutive Whole Numbers Are Such That The Square Of The Middle Number Is Greater Than The Product Of The Other Two By 1. Find The Middle Number?


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Oddman answered
This will be true for any three consecutive integers.

Suppose the middle one is "a".
The product of the other two is (a-1)*(a+1) = a^2 - 1. The square of the middle number, a^2, is greater than this amount by 1, regardless of the value of "a".

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