This will be true for

Suppose the middle one is "a".

The product of the other two is (a-1)*(a+1) = a^2 - 1. The square of the middle number, a^2, is greater than this amount by 1, regardless of the value of "a".

*three consecutive integers.***any**Suppose the middle one is "a".

The product of the other two is (a-1)*(a+1) = a^2 - 1. The square of the middle number, a^2, is greater than this amount by 1, regardless of the value of "a".