Let x = the larger number
y = the smaller number
x + y = 51
x - y = 13 ==> x = y + 13
substitute y + 13 back into the first equation and solve for y
(y + 13) + y = 51
2y + 13 = 51
2y + 13 - 13 = 51 - 13
2y = 38
2y/2 = 38/2
y = 19
substitute 19 for y back into either equation
x - 19 = 13
x - 19 + 19 = 13+ 19
x = 32
substitute both x and y values back into other equation as a check
32 + 19 = 51
51 = 51
so, the larger number, x = 32, and the smaller number, y = 19
y = the smaller number
x + y = 51
x - y = 13 ==> x = y + 13
substitute y + 13 back into the first equation and solve for y
(y + 13) + y = 51
2y + 13 = 51
2y + 13 - 13 = 51 - 13
2y = 38
2y/2 = 38/2
y = 19
substitute 19 for y back into either equation
x - 19 = 13
x - 19 + 19 = 13+ 19
x = 32
substitute both x and y values back into other equation as a check
32 + 19 = 51
51 = 51
so, the larger number, x = 32, and the smaller number, y = 19