Peggy had three times as many quarters as nickels. She had $1.60 in all. How many nickels and how many quarters did she have? Which of the following equations could be used to solve the problem?


1 Answers

Oddman Profile
Oddman answered
Each group of 3 quarters and 1 nickel is worth $0.80. Peggy had 1.60/0.80 = 2 such groups.
Peggy had 6 quarters and 2 nickels.

  q = 3n
  .25q + .05n = 1.60
Substituting, we get
  .25(3n) + .05n = 1.60
  which resolves to
  .80n = 1.60
This is identical to the description of the solution we used above.

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