The height of a falling object can be approximated (assuming no air resistance) by

h(t) = -16t^2 + h0

where h0 is the initial height of the object.

We are given h(5.6) = 0 and are asked to find h0.

0 = -16*5.6^2 + h0

16*5.6^2 = h0

501.76 = h0

We are given time measured to 2 significant digits, so our answer can be no more accurate than 2 significant digits. If you want more significant digits than that, you must also use a more precise number for the standard gravity constant.

(9.80665 m/s^2)/(2*.3048 m/ft) = 196133/12192 ft/s^2 ≈ 16.0870242782 ft/s^2

The metric value of standard gravity is a definition, so is exact.

h(t) = -16t^2 + h0

where h0 is the initial height of the object.

We are given h(5.6) = 0 and are asked to find h0.

0 = -16*5.6^2 + h0

16*5.6^2 = h0

501.76 = h0

**The height of the building is about 500 ft.**We are given time measured to 2 significant digits, so our answer can be no more accurate than 2 significant digits. If you want more significant digits than that, you must also use a more precise number for the standard gravity constant.

(9.80665 m/s^2)/(2*.3048 m/ft) = 196133/12192 ft/s^2 ≈ 16.0870242782 ft/s^2

The metric value of standard gravity is a definition, so is exact.