If production is on-going and if tasks are done by different resources, the rate is limited by Task 2. That task can be completed
25/(3 1/6) = 25*6/19 ≈ 7.89
times in 25 minutes. 7 items can be completed.
If a resource must complete all 3 tasks on one item before working on the next, then the number that can be produced in 25 minutes is
25/(2 1/2 + 3 1/6 + 1)
= 25/(20/3)
= 75/20
= 3.75.
3 items can be completed in a 25-minute period.
If the production line must be started, but tasks are done by different resources, the rate is limited by Task 2 and the other task times need to be subtracted from the time available.
(25 - 2 1/2 - 1)/(3 1/6)
= (43/2)/(19/6)
= 129/19
≈ 6.79.
6 items can be completed in the first 25 minutes of production.
The problem is not described very well. One should be able to assume that on an assembly line, the tasks will be done by different resources. Each of the answers here has a fractional part, meaning that in some 25-minute intervals N items will be assembled and in other 25-minute intervals (N+1) items will be assembled.
25/(3 1/6) = 25*6/19 ≈ 7.89
times in 25 minutes. 7 items can be completed.
If a resource must complete all 3 tasks on one item before working on the next, then the number that can be produced in 25 minutes is
25/(2 1/2 + 3 1/6 + 1)
= 25/(20/3)
= 75/20
= 3.75.
3 items can be completed in a 25-minute period.
If the production line must be started, but tasks are done by different resources, the rate is limited by Task 2 and the other task times need to be subtracted from the time available.
(25 - 2 1/2 - 1)/(3 1/6)
= (43/2)/(19/6)
= 129/19
≈ 6.79.
6 items can be completed in the first 25 minutes of production.
The problem is not described very well. One should be able to assume that on an assembly line, the tasks will be done by different resources. Each of the answers here has a fractional part, meaning that in some 25-minute intervals N items will be assembled and in other 25-minute intervals (N+1) items will be assembled.
