The total surface area of a cuboid of dimensions l, w, h is given by

area = 2(lw + lh + wh)

Substituting the given dimensions in meters, we have

.94 m^2 = 2((.7 m)(.5 m) + (.7 m)(h) + (.5 m)(h))

.47 = .35 + h(1.2) (divide by 2 m^2, consider h to be in meters; collect terms)

.12 = 1.2h (subtract .35)

.12/1.2 = h (divide by 1.2)

.10 = h

area = 2(lw + lh + wh)

Substituting the given dimensions in meters, we have

.94 m^2 = 2((.7 m)(.5 m) + (.7 m)(h) + (.5 m)(h))

.47 = .35 + h(1.2) (divide by 2 m^2, consider h to be in meters; collect terms)

.12 = 1.2h (subtract .35)

.12/1.2 = h (divide by 1.2)

.10 = h

**The height of the cuboid is 10 cm.**