Nitroglycerin (C3H5N3O9) is a powerful explosive. Its decomposition is C3H5N3O9=6N2+12CO2+10H2O+O2. What is the number of O2 molecules from 2 x 10^2 grams of nitroglycerin? What is the % yield if 6.55 grams of O2 were collected?

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John McCann Profile
John McCann answered
4C3H5N3O9 -> 6N2 + 12CO2 + 10H2O + O2

This is not balanced! Now it is! Don't forget all coefficients again!

2 X 10^2 grams Nitro (1 mole Nitro/227.1 grams)(1 mole O2/4 mole Nitro)(6.022 X 10^23/1 mole O2)

= 1.33 X 10^23 molecules O2
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1.33 X 10^23 molecules O2 (1 mole O2/6.022 X 10^23)(32.0 grams/1 mole O2)

= 7.05 gram
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6,55 grams/7.05 grams

92.9% is the yield
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I see you have a lot of problems. If you do not try to work some yourself you will fail chemistry. Chemistry is in the doing.
thanked the writer.
cindy slade
cindy slade commented
These are just a few of the ones that I want to make sure I have fiqured right. Sometimes the answers don't look right. Thanks.
John McCann
John McCann commented
OK if you are double checking.

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