Can You Find The First,fourth,and Tenth Terms Of The Arithmetic Sequence Described By The Given Rule. A(n)=-6+(n-1)(1/5)?

A(n) = -6 +(n-1)1/5
Here
A(n) is the nth term
First term a = -6
Different d = 1/5
Term n = n

For first term n = 1
A(n) = -6 +(n-1)1/5
A(1) = -6 +(1-1)1/5
A(1) = -6 +(0)1/5
A(1) = -6 +0
A(1) = -6

So first term = -6

Fourth term n = 4
A(n) = -6 +(n-1)1/5
A(4) = -6 +(4-1)1/5
A(4) = -6 +(3)1/5
A(4) = -6 +3/5
A(4) = (-30+3)/5
A(4) = (-27)/5

So fourth term = -27/5

Tenth term n = 10
A(n) = -6 +(n-1)1/5
A(10) = -6 +(10-1)1/5
A(10) = -6 +(9)1/5
A(10) = -6 +9/5
A(10) = (-30+9)/5
A(10) = (-21)/5

So tenth term = -21/5