Can You Find An Equation Of A Line That Contains The Origin And The Given Point (2, -2).?

The equation of line when two points are given is;

(x-x₁)/(x₂-X₁) = (y-y₁)/(y₂-y₁)

in the given question;

(x₁, y₁) = origin = (0, 0)

(x₂, y₂) = (2, -2)

Put values in general equation;

(x - 0) / (2- 0) = (y - 0)/(-2- 0)

x / 2 = y/ -2

-2x = 2y

Dividing by 2 on both sides

y = -x

This is the required equation of line. It is a straight line and present in second and fourth quadrant.