The general equation of a line which passes through (x0,y0) is
(y - y0) = m*(x - x0) m - is the slope of the line
slope = how many units does a close climb/descends on a specified horizontal distance
Lets consider (x0,y0) = (-2,1)
The equation of a line that passes through (-2,1) is
y-1 = m(x+2)
In order for it to pass through the second point (x1,y1)=(5,-2) we have to specify an appropriate slope.
M=(y0-y1)/(x0-x1) - see the definition above
so m is
m=(-2-1)/(5-(-2)) = -3/7
your answer is
y-1 = -3/7 * (x+2)
(y - y0) = m*(x - x0) m - is the slope of the line
slope = how many units does a close climb/descends on a specified horizontal distance
Lets consider (x0,y0) = (-2,1)
The equation of a line that passes through (-2,1) is
y-1 = m(x+2)
In order for it to pass through the second point (x1,y1)=(5,-2) we have to specify an appropriate slope.
M=(y0-y1)/(x0-x1) - see the definition above
so m is
m=(-2-1)/(5-(-2)) = -3/7
your answer is
y-1 = -3/7 * (x+2)
