Write an equation for the line that passes through the points (0, -6) and (-3, 0)?

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2 Answers

Oddman Profile
Oddman answered
The given points are readily observed to be the y- and x-intercepts, respectively. Thus, a good place to start is with intercept form.
  x/(-3) + y/(-6) = 1    (this is an equation for the line)
  2x + y = -6    (multiply by -6 to get Standard Form)
  y = -2x - 6    (subtract 2x to get slope-intercept form)
John McCann Profile
John McCann answered
First, m = Y2 - Y1/X2 - X1

m = 0 - 6/- 3 - 0

m = 2
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Now we use the point slope form Y - Y1 = m(X - X1)

Y - (- 6) = 2[ X - (- 3)]

Y + 6 = 2(X + 3)

Y + 6 = 2X + 6

Y = 2X
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