Find the equation of the line that passes through the point (5, 6) and has slope m = –4. Write your answer in point-slope form?

2 Answers

Learning2Learn Profile
Learning2Learn answered
1)
slope = 2, point (1, 6)
(y - 6) = 2(x - 1)
y - 6 = 2x - 2
y = 2x + 4

2)
slope = -1/5, point (5, 4)
(y - 4) = (-1/5)(x - 5)
y - 4 = (-1/5)x + 1
y = (-1/5)x + 5

3)
slope = 4/3, point (12, 1)
(y - 1) = (4/3)(x - 12)
y - 1 = (4/3)x - 16
y = (4/3)x - 15

4)
slope = 0, y-intercept -3
y = -3

5)
slope = 2, point (-3, -10)
(y + 10) = 2(x + 3)
y + 10 = 2x + 6
y = 2x - 4

6)
slope = 1/2, point = (-2, 4)
(y - 4) = (1/2)(x + 2)
y - 4 = (1/2)x + 1
y = (1/2)x + 5

7)
slope = 5/4, point (4, -8)
(y + 8) = (5/4)(x - 4)
y + 8 = (5/4)x - 5
y = (5/4)x - 13

There, you have your lines
Oddman Profile
Oddman answered
There are a couple of different point-slope forms. One I learned is
  y - k = m(x - h)
for point (h, k) and slope m. By adding k, you can get another form that is commonly seen
  y = m(x - h) + k

Using the latter form, your line is
  y = -4(x - 5) + 6

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