It takes the car (40 ft/s)/(7 ft/s^2) = 5 5/7 s to stop. In that time, it will have traveled

(1/2)*(5 5/7 s)*(40 ft/s) =

Consider a plot of velocity versus time. It starts at 40 ft/s and decreases linearly to 0 with a slope of -7 ft/s*2. The velocity will reach 0 at 5 5/7 seconds. The area of the triangle is the distance traveled. It is computed as 1/2*base*height = 1/2*(5 5/7 s)*(40 ft/s).

(1/2)*(5 5/7 s)*(40 ft/s) =

**114 2/7 ft**Consider a plot of velocity versus time. It starts at 40 ft/s and decreases linearly to 0 with a slope of -7 ft/s*2. The velocity will reach 0 at 5 5/7 seconds. The area of the triangle is the distance traveled. It is computed as 1/2*base*height = 1/2*(5 5/7 s)*(40 ft/s).