Anonymous

How Do You Solve Sec(-x)cot X?

3 Answers

Anonymous Profile
Anonymous answered
sec(-x)cotx put secx=1/cosx
and cotx=cosx/sinx

=> -(1/cosx)*(cosx/sinx)
=> -(1/sinx)
put 1/sinx=cosecx
=> -cosecx

So Sec(-x)cot x = -cosec x


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amber Jhon Profile
amber Jhon answered
It is a question of trigonometric functions.

Sec(-x)cot X

since Secx= 1/because x

So,

Sec(-x)cot X= 1/ because(-x)  Cot x

as because(-x)= Cosx, So

Sec(-x)cot X=1/Cosx  Cotx

Put Cotx= because x/ Sinx, we get

Sec(-x)cot X= 1/Cosx * because x/ Sin x  

Sec(-x)cot X=Cosx/ Cosx * 1/Sin x

Sec(-x)cot X= 1* 1/Sinx

Sec(-x)cot X= 1/ Sinx

we know that 1/ Sin x= Cosec x

So,

Sec(-x)cot X= Cosec x

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Anonymous