# Find the ordered triple (a, b, c) which satisfies... a(x-1)(x+2)+b(x-1)(x+1)+c(x+2)(x+1)=6x+12?

a. (X -1)(X + 2)

b. (X - 1)(X + 1)

c. (X + 2)(X + 1)

------------------------------------And they're to satisfy, 6X + 12 ??????

FOIL all.

a. = X^2 + X - 2

b. = X^2 - 1

c. = X^2 + 3X + 2

___________________I will be back.

Where is the ordered triple, X, Y, Z? All I could find here would be the value of X and there are not three variables here. Just looking at the expressions tell you the negative and positive X.

a. = (1 - 1)(- 2 + 2)

b. = (1 - 1)(- 1 + 1)

c. = (- 2 + 2)(- 1 + 1)

Usually with ordered triples you find the variable values one by one with manipulation of the expressions/equations and you keep inserting values into these expressions/equations to find the value of all three variables. I'm missing something here.

2 People thanked the writer.
Jaimie JT commented
When you say you'll be back does that mean you didn't know the answer ???? Or was that the answer ? And what the heck is foil all ?
John McCann commented
FOIL means

First, outer, inner, and last. It is how you multiply out an expression such as this...,

((X - 1)(X + 2)

multiply first ( X * X ), outer (X * 2), inner (X * - 1 ), and last (- 1 * 2).

Gather terms and you have a quadratic expression.

I don't know the answer as this problem seems incomplete or incoherent. 