There are three variables in this question and I will derive the value of one and insert it in the other equation.
15z = 3y
y = 15z/3
y = 5z
or z = 0.2y
Putting the value of z in the equation:
R = 5(0.2z)
R = z
15z = 3y
y = 15z/3
y = 5z
or z = 0.2y
Putting the value of z in the equation:
R = 5(0.2z)
R = z