Y ∝ 1/x

y=k/x

k=y times x

5=k/7

k=7x5=35

y=35/4

y=8.75

y=k/x

k=y times x

5=k/7

k=7x5=35

y=35/4

y=8.75

Y ∝ 1/x

y=k/x

k=y times x

5=k/7

k=7x5=35

y=35/4

y=8.75

y=k/x

k=y times x

5=k/7

k=7x5=35

y=35/4

y=8.75

When the variation is inverse,

x1*y1 = x2*y2

(7)(5) = (4)*y2

y2 = 35/4

The value you seek is y = 8 3/4.

x1*y1 = x2*y2

(7)(5) = (4)*y2

y2 = 35/4

The value you seek is y = 8 3/4.

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