Y ∝ 1/x
y=k/x
k=y times x
5=k/7
k=7x5=35
y=35/4
y=8.75
y=k/x
k=y times x
5=k/7
k=7x5=35
y=35/4
y=8.75
If Y Varies Inversely With X, And Y = 5 When X = 7, What Is The Value Of Y When X = 4?
When the variation is inverse,
x1*y1 = x2*y2
(7)(5) = (4)*y2
y2 = 35/4
The value you seek is y = 8 3/4.
x1*y1 = x2*y2
(7)(5) = (4)*y2
y2 = 35/4
The value you seek is y = 8 3/4.