This is a very simple equation. You can solve it both by the factorization method and by applying the quadratic equation.
Let's look at how we can solve it by factorization:
x2+12x-64 = 0
x2+16x-4x-64 = 0
x(x+16)-4(x+16) = 0
(x-4)(x+16) = 0
x-4 = 0
or
x+16 = 0
x-4 = 0
x = 4
x+16 = 0
x = -16
So, x is equal to either 4 or -16. ----ANSWER
You can also solve this by applying the values into the quadratic formula. The quadratic formula is:
x=-b±√b2-4ac
2a
Where, a=1
b=12
c=-64
Let's look at how we can solve it by factorization:
x2+12x-64 = 0
x2+16x-4x-64 = 0
x(x+16)-4(x+16) = 0
(x-4)(x+16) = 0
x-4 = 0
or
x+16 = 0
x-4 = 0
x = 4
x+16 = 0
x = -16
So, x is equal to either 4 or -16. ----ANSWER
You can also solve this by applying the values into the quadratic formula. The quadratic formula is:
x=-b±√b2-4ac
2a
Where, a=1
b=12
c=-64
