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How Do You Solve X2+12x-64=0?

2 Answers

Katie Harry Profile
Katie Harry answered
This is a very simple equation. You can solve it both by the factorization method and by applying the quadratic equation.

Let's look at how we can solve it by factorization:

x2+12x-64 = 0
x2+16x-4x-64 = 0
x(x+16)-4(x+16) = 0
(x-4)(x+16) = 0

x-4 = 0
or
x+16 = 0

x-4 = 0
x = 4

x+16 = 0
x = -16

So, x is equal to either 4 or -16. ----ANSWER

You can also solve this by applying the values into the quadratic formula. The quadratic formula is:
x=-b±√b2-4ac
  2a
Where,  a=1
  b=12
  c=-64

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