Let the area of the square be represented by A. Then one side of the square is √A, and the diagonal of the square (the diameter of the circle) is √(2A).
The area of a circle is
area = π(d/2)^2 = (π/4)d^2
Our circle has diameter d = √(2A), so the area of our circle is
area = (π/4)(√(2A))^2
= 2πA/4
= (π/2)A
The area of a circle is
area = π(d/2)^2 = (π/4)d^2
Our circle has diameter d = √(2A), so the area of our circle is
area = (π/4)(√(2A))^2
= 2πA/4
= (π/2)A