You Place A Box Weighing 220.4 N On An Inclined Plane That Makes A 38.6◦ Angle With The Horizontal. Compute The Component Of The Gravitational Force Acting Down The Inclined Plane. Answer In Units Of N?


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Oddman Profile
Oddman answered
The force acting parallel to the surface of the plane is the sine of the angle of elevation times the force acting "down."
  220.4*sin[38.6°] = 220.4*0.6 = 132.24
Your force is 132.24 N down the plane.

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