(x-4)(2x^2-7x+8)= 2x^3-8x^2-7x^2+28x+8x-32=2x^3-15x^2+36x-32
Can You Multiply(x-4)(2x^2-7x+8) And Show All Work?
(x - 4)(2x2 - 7x + 8) = x(2x2 - 7x + 8) - 4(2x2 - 7x + 8) (use distributive property)
= (2x3 - 7x2 + 8x) + (-8x2 + 28x - 32) (use distributive property again)
= 2x3 + x2(-7 - 8) + x(8 +28) - 32 (combine like terms)
= 2x3 - 15x2 + 36x - 32
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Zuzka23 distributed the terms the other way:
(x - 4)(2x2 - 7x + 8) = 2x2(x-4) -7x(x-4) +8(x-4)
I personally find the continual switching between powers of x to be less easy to deal with when multiplying out the next step.
= (2x3 - 7x2 + 8x) + (-8x2 + 28x - 32) (use distributive property again)
= 2x3 + x2(-7 - 8) + x(8 +28) - 32 (combine like terms)
= 2x3 - 15x2 + 36x - 32
_____
Zuzka23 distributed the terms the other way:
(x - 4)(2x2 - 7x + 8) = 2x2(x-4) -7x(x-4) +8(x-4)
I personally find the continual switching between powers of x to be less easy to deal with when multiplying out the next step.