Let's solve the quadratic equation:

2x^2+7x = 5

First we need to put the equation in the form:

ax^2 + bx + c = 0

For this, we set the equation to equal 0, and arrange the terms from the highest exponent to the lowest:

2x^2+7x-5 = 0

We have:

a=2 b=7 c=-5

We can now apply the quadratic formula:

x = ( -b ± √(b²-4ac) ) / 2a

We find two solutions:

x=0.60849528301415 or x=-4.1084952830142

OR

First we need to put the equation in the form:

ax^2 + bx + c = 0

For this, we set the equation to equal 0, and arrange the terms from the highest exponent to the lowest:

2x^2+7x-5 = 0

We have:

a=2 b=7 c=-5

We can now apply the quadratic formula:

x = ( -b ± v(b²-4ac) ) / 2a

We find two solutions:

x=0.60849528301415 or x=-4.1084952830142

2x^2+7x = 5

First we need to put the equation in the form:

ax^2 + bx + c = 0

For this, we set the equation to equal 0, and arrange the terms from the highest exponent to the lowest:

2x^2+7x-5 = 0

We have:

a=2 b=7 c=-5

We can now apply the quadratic formula:

x = ( -b ± √(b²-4ac) ) / 2a

We find two solutions:

x=0.60849528301415 or x=-4.1084952830142

OR

First we need to put the equation in the form:

ax^2 + bx + c = 0

For this, we set the equation to equal 0, and arrange the terms from the highest exponent to the lowest:

2x^2+7x-5 = 0

We have:

a=2 b=7 c=-5

We can now apply the quadratic formula:

x = ( -b ± v(b²-4ac) ) / 2a

We find two solutions:

x=0.60849528301415 or x=-4.1084952830142

Subtract 5 from each side, then...

Factor it out

Factor it out

(2x+3)(x-2)

seperate and solve for two possible answers

2x+3=0, where x=-3/2

x-2=0, where x=2

seperate and solve for two possible answers

2x+3=0, where x=-3/2

x-2=0, where x=2

2x

Or, 2x

here,

a=2 b=7 c=-5

applying the quadratic formula-

x = ( -b ± √(b²-4ac) ) / 2a

x=

^{2}+ 7x=5Or, 2x

^{2}+ 7x-5=0here,

a=2 b=7 c=-5

applying the quadratic formula-

x = ( -b ± √(b²-4ac) ) / 2a

x=

**0.60849528301415**or x=-**4.1084952830142**