suppose jay has travlled x miles,ben has travelled 8-x miles and they meet after time t

for jay: d=x mile, t=t hour and r=5mph

therefore x=5 t

or t=x/5 ...(1)

for ben: d=(8-x) mile, t=t hour and r=7mph

therefore 8-x=7 t

or t=(8-x)/5 ...(2)

from eqns.1 and 2

we have

x/5 = (8-x)/7

or 7x = 40-5x

or x = 40/12 = 3.333 miles

so jay travels 3.333 miles

and ben travels =8-3.333=4.67miles,so ben travels longer distance

combined distance travelled is 8 miles

time at which they meet = 3.333/5=.6666 hrs or 66.66 mins

for jay: d=x mile, t=t hour and r=5mph

therefore x=5 t

or t=x/5 ...(1)

for ben: d=(8-x) mile, t=t hour and r=7mph

therefore 8-x=7 t

or t=(8-x)/5 ...(2)

from eqns.1 and 2

we have

x/5 = (8-x)/7

or 7x = 40-5x

or x = 40/12 = 3.333 miles

so jay travels 3.333 miles

and ben travels =8-3.333=4.67miles,so ben travels longer distance

combined distance travelled is 8 miles

time at which they meet = 3.333/5=.6666 hrs or 66.66 mins