How Do I Solve This Problem? 3x+4y=-2 X=2y

3x-y=5, x-4y =-2

5x+4y-2/2y+3

3x+4y=-2...(1)
x=2y...(2)
put the value of x from eq. (2) to eq.(1)
3*(2y)+4y=-2
6y+4y=-2
10y=-2
y=-1/5
put the value of y into eq.(2)
x=2*(-1/5)
x=-2/5
values are : X=-2/5 and y=-1/5

There are two equations in the problem;
3x+4y=-2x, 3x+4y=2y
There are two variables in the problem x and y so we would have to take a variable´s value from one equation,
3x+4y=-2x
3x+2x+4y-4y=-2x+2x-4y
5x=-4y
x=-4y/5

Putting the value of x in second equation;
3x+4y=2y
3(-4y/5)+4y-4y=2y-4y
12y/5=-2y
12y/5+2y=-2y+2y
taking LCM
(12y+10y)/5=0
22y/5 x 5=0x5
22y=0
22y/22=0/22
y=0

Putting the value of y in first equation
x=-4y/5
x=-4(0)/5
x=0

so, x=0 and y=0 or (x,y)=(0,0)

2x-2y=-14
4x-y=22
the solution is